Dahil hindi naman ako makatulog ...
Here's comparison data of
Induction Gas vs LPG from Wikipedia I used as basis for computation:
Energy consumption when boiling 2 litres of water (from 20 degrees Celsius)
Induction stove 745 kJ
Gas 1700 kJ
Because of the high efficiency of induction cookers, it takes 43% less energy to boil 2 liters of water.
Given the following Energy Densities:
Electricity ... 1 kW = 3,600 MJ
LPG ... 11kg x 50.4 per kg = 554.4 MJ
... and using the following fuel prices:
Electricity - P 8.70 per KWH
LPG - P 710.00 per 11kg cylinder
Therefore the cost of fuel for boiling 2L of water used above are as follows:
Induction Stove: 0.00180041666667 PHP
LPG : 2.17712842712843 PHP
PS
All of the above is correct, unless it's not. I failed Algebra 101 during my froshie year in Uni ....
PPS
Spreadsheet calcuations:
Cost of Fuel MJ / Unit of Energy Consumption (MJ) Cost of Fuel Consumed
8.7 3600 0.745 0.02% 0.00180042
710 554.4 1.7 0.31% 2.17712843
sir, 1kWh = 3.6MJ lang not 3600MJ. 1Wh = 3600J since 1 Ws = 1J. 3600J x 1000 = 3.6MJ.
to verify, eto online calculator sir.
http://www.convertunits.com/from/kWh/to/joules.745MJ / 3.6MJ * (average 8 to 10 PhP / kWh) = 1.60 to 2.00 PhP to boil 2 liter of water.
There might be some stuff not yet included like for example the transfer of heat

It takes considerable amount of time to transfer heat. Although I failed many times in chemistry >.<. They never gave questions how long it would take to boil 1 liter of water. They only mentioned how much energy it takes though.
kasama na 'yung consideration ng power at time sa energy sir. since 1J = 1 Nm, 1Ws = 1 Nm/s * s, 1Ws = 1J, 1kWh = 3.6MJ.
kinuha 'yung efficiency ng system using calorimeter at sa table stated din 'yung time. meaning kasama na 'yung transfer of heat from magnet to cookware at open flame to cookware.