ian23jess
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« on: February 27, 2010, 01:13:33 PM » |
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mga sis!  ano po ang masusukat nyo na voltage reading if one is 12v 7ah is connected in parallel to a 6v 7ah battery? kagaya po b ito ng capacitor? kasi may nakapag sabi sa akin na ang masusukat mo doon ay yung may mataas na reading.. which is 12v tama po ba un?
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« on: February 27, 2010, 01:13:33 PM » |
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ultrasonic™
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« Reply #1 on: February 27, 2010, 01:43:04 PM » |
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yapz 12V nga ang masusukat mu dahil yan ang pinakamataas
then add mu ang current rating ng bawat isang batterya yan ang total current mu
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rdpzycho
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« Reply #2 on: February 27, 2010, 02:36:55 PM » |
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subukan niyo.  mag-act as load 'yung 6V doon sa parallel configuration. since mababa ang series resistance nung 12V (around 20milliohms), I = (12 - 6) / (20milliohms) = catastrophe.  nagpa-parallel lang ng batteries if they are of equal voltage and equal capacity (Ah rating), otherwise merong isang mauunang masira, if not both. sa capacitors kasi voltage rating lang 'yun, hindi talaga siya ang nagso-source ng current (temporary storage lang siya).
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"Keep on starting, and finishing will take care of itself."
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,,V, (@_@) ,V,,
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« Reply #3 on: February 27, 2010, 04:17:37 PM » |
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Paepal lng  >Yung millman's the0rem pde ba gamitin dit0??? >Tsaka pan0 ko malalaman ung internal resistance ng batt? Ganito ba: 12V/7ah= 1.714 ohms??? 6V/7ah= 0.857 ohms??
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Wla lng!
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rdpzycho
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« Reply #4 on: February 27, 2010, 08:17:09 PM » |
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nope. given 'yun sa datasheet. 
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"Keep on starting, and finishing will take care of itself."
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ian23jess
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« Reply #5 on: March 04, 2010, 12:37:05 PM » |
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thanks guys!! enough na ung explanation nyo.. 
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DigitalMind
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« Reply #6 on: March 04, 2010, 12:40:10 PM » |
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subukan niyo.  mag-act as load 'yung 6V doon sa parallel configuration. since mababa ang series resistance nung 12V (around 20milliohms), I = (12 - 6) / (20milliohms) = catastrophe.  nagpa-parallel lang ng batteries if they are of equal voltage and equal capacity (Ah rating), otherwise merong isang mauunang masira, if not both. sa capacitors kasi voltage rating lang 'yun, hindi talaga siya ang nagso-source ng current (temporary storage lang siya). oh... kaya pala walang naka parallel sa mga battery packs. thanks!
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I n s i d e r 2010
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« Reply #7 on: March 04, 2010, 12:50:00 PM » |
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sira ang plates ng 6 volts battery mo pag ganun
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ang PIKON ay laging TALO,tandaan nyo po yan mga kapatid. IRESPETO ang bawat isa! ang PANLALAIT sa kapwa ay isang kasalanan na pagbabayaran mo rin balang araw!
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toasted siopao
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« Reply #8 on: March 04, 2010, 12:57:06 PM » |
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yapz 12V nga ang masusukat mu dahil yan ang pinakamataas
then add mu ang current rating ng bawat isang batterya yan ang total current mu
Nope, 6V ang masusukat. Mas lower ang resistance ng 6V mo compared sa 12V.
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I n s i d e r 2010
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« Reply #9 on: March 04, 2010, 01:10:13 PM » |
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Nope, 6V ang masusukat. Mas lower ang resistance ng 6V mo compared sa 12V.
sure kba jan sis? kapag parehas na full charged ang 12 at 6 volts battery mo at connected sa parallel sure ang masusukat na voltahe ay yung pinakamataas kung drain naman yung 12 volts battery mo at full charged ung 6 volts sure ang masusukat ay ung pinakamataas parin na voltahe at 6 volts parin yun kz drain na nga yung 12 volts battery kung parehas naman na drain na sure ala ng masusukat kung parehas naman na full charged ung dalawang battery na magkaiba ng voltahe sure na isa sa kanila ang masisira at ung 6 volts nga ang masisira kz parang kinabitan mo ng charger na overvolt at paktay ang plates nun korek si master ultra na 12 volts ang masusukat dun pero may point din si sis gleenjoy - yan ay kung sira na or ala ng laman ung 12 volts battery
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ang PIKON ay laging TALO,tandaan nyo po yan mga kapatid. IRESPETO ang bawat isa! ang PANLALAIT sa kapwa ay isang kasalanan na pagbabayaran mo rin balang araw!
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rdpzycho
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« Reply #10 on: March 04, 2010, 03:10:01 PM » |
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kapag pinag-parallel 'yan, ang masusukat mas malapit sa 6V dahil magiging load siya nung 12V. magiging halos shorted kasi 'yung 12V. kapag sinubukan 'yan, magkakaroon ng sobrang lakas na sparking. remember 'yung basic charger na rectified and filtered lang, nasa 16V 'yun pero kapag sinaksak 'yung battery bababa sa terminal voltage 'yung masusukat. doon sa parallel batteries, magiging 12V ang masusukat kung may sira 'yung 6V i.e. high impedance na siya at hindi tumatanggap ng charge.
kung ilalagay sa mechanical dual 'yan, example merong isang motor na umiikot ng 3600 RPM at isa sa 1800 RPM pagkakabitin sa isang rigid shaft, mahihila pabilis nung 3600 'yung 1800, pero hindi niya masasagad sa speed nung 3600 dahil 'yung poles nung motor na 1800 umiikot din merong kumokontra.
sa bike naman na pang-dalawang tao na coupled ang pedal, kung mabagal mag-pedal 'yung isa, babagal din 'yung isa dahil nagiging pabigat mag-pedal 'yung mabagal.
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"Keep on starting, and finishing will take care of itself."
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Woots29
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« Reply #11 on: March 04, 2010, 03:25:38 PM » |
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toasted siopao
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« Reply #13 on: March 04, 2010, 03:48:05 PM » |
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Told yah, it is 6V, reason behind, shortest path.
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7_SeVeN_7
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« Reply #14 on: March 04, 2010, 04:03:32 PM » |
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^^ agree ako kay sis glenjoy (ikaw na daw yata ang susunod sa boiling point/melting point) 
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E-Gizmo Mechatronix Central: www.e-gizmo.comTel #: (63)(2) 536-3378 Globe +63915-973-7691 Smart +63921-779-0748 Location MapYM: julie.egizmo aka Born2BeWired 
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Born2BeWired
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« Reply #15 on: March 04, 2010, 04:22:15 PM » |
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Kay rdp ako  You don't parallel two batteries with dissimilar voltage. Let me offer an explanation from another perspective. Imagine the two batteries with the negative side already connected together, and with the positive side still left unconnected. If you measure the the voltage difference between the two positive terminals, you will measure the full potential difference, which is 12V-6V = 6V. In other words, at this condition, you have in effect a single battery with an open circuit voltage of 6V. Connecting the two positive together is no different from shorting a single 6V battery. You will most probably destroy both batteries. The battery with lower V*I rating (not necessarily the one with higher voltage) will go first.
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ian23jess
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« Reply #16 on: March 04, 2010, 05:46:43 PM » |
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wow galing naman!!! lubos akong natutuwa sa mga reply nyo! marami talagang matutunan dito.. maraming salamat po!
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7_SeVeN_7
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« Reply #17 on: March 04, 2010, 06:05:19 PM » |
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ganda point kay tita boy 
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E-Gizmo Mechatronix Central: www.e-gizmo.comTel #: (63)(2) 536-3378 Globe +63915-973-7691 Smart +63921-779-0748 Location MapYM: julie.egizmo aka Born2BeWired 
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rdpzycho
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« Reply #18 on: March 04, 2010, 06:18:54 PM » |
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wow galing naman!!! lubos akong natutuwa sa mga reply nyo! marami talagang matutunan dito.. maraming salamat po!
BTW, huwag niyong subukan with actual batteries.  lalo na kung manipis na wire ang gamit, at hawak mo, magkakaroon ka ng malalim na burn mark.  most of those batteries have short circuit current ratings of 150A to 250A, can melt the wire's coating in fractions of a second. 
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"Keep on starting, and finishing will take care of itself."
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I n s i d e r 2010
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« Reply #19 on: March 04, 2010, 08:10:10 PM » |
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para sa actual voltage measurement
gamit nalang tayo ng 1.5 volts battery (double A ng mas mura)
isang battery - 1.5 volts
iparallel sa 2 pcs 1.5 volts na nakaseries
pakisukat nalang kung ano talaga ang actual reading
parehas din siguro yan ng 12 at 6 volts
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ang PIKON ay laging TALO,tandaan nyo po yan mga kapatid. IRESPETO ang bawat isa! ang PANLALAIT sa kapwa ay isang kasalanan na pagbabayaran mo rin balang araw!
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The Philippine Electronics and Technology Forum
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