Physics

[Akon]

my favorite subject is phyics  . i may be able to help if you have assignments on physics.

[frfefarfearz]

a frsh physics grad here ^_^

[switch_link]

interesting to... pero wala naman ata gusto mag-open ng topic.. sayang 

[underprezzure]

interesting to... pero wala naman ata gusto mag-open ng topic.. sayang 

Meron na . Ito oh

http://www.electronicslab.ph/forum/index.php?topic=1682.0

at ito:

http://www.electronicslab.ph/forum/index.php?topic=1685.0

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[mArKhAo]

hehe, nsan ang center of gravity ng donut hehehe...

[underprezzure]

hehe, nsan ang center of gravity ng donut hehehe...

serious question ba to? papatulan ko ng seryosong sagot kung serious nga ito. 

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[mArKhAo]

hehe, once na yan natanung ng prof namin... 

[underprezzure]

hehe, once na yan natanung ng prof namin... 

Explaination is here .

http://www.grc.nasa.gov/WWW/K-12/airplane/cg.html

It is already self explainatory sa site na yan. so need to explain further.


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[mArKhAo]

hehe,, check nyu po ung thread sa GEAS, : Nasaan ang center of gravity ng..............

[switch_link]

Explaination is here .

http://www.grc.nasa.gov/WWW/K-12/airplane/cg.html

It is already self explainatory sa site na yan. so need to explain further.


-underpazz campaigns for more post on technical threads

wer yung para sa donut "toroid" bakit wala?? waaahhh!!!!
cguro nasa DUNKIN.. o kaya sabi dun sa kabilang thread ginawa na daw munchkins

[switch_link]

hehe,, check nyu po ung thread sa GEAS, : Nasaan ang center of gravity ng..............

oo na-check ko na po... nasa munchkin nga!

[m4go10]

pa help po mga masters: e2 serious talaga..

A stone is thrown upward with an initial speed of 16 m/s
a.   What will be its maximum height?
b.   When will it return to the ground?


paki indicate lng po wat formulas ung ginamit.. tnx po..

[ekajara_josh]

Let s = distance traveled by the stone.
      t = time taken to travel that distance.
      Vi = initial velocity of the stone.
      Vf = final velocity.
      g = acceleration due to gravity.(w/c is 9.8 m/s^2)
Possible formulas:

        s = Vit + 1/2gt^2
        Vf = Vi +/- gt (+g if the object goes downward/same direction of the pull of gravity.)
                              (-g if the object goes upward/opposite direction to the pull of gravity.)

Given:
 Vi = 16 m/s
Solution:

Since the direction of the object was opposite to the pull of gravity, we use -g.
Isa pa, kung ma-reach na ng object(w/c is stone) ang maximum height na maaabot nito, ang value ng Vf = 0(zero).

Derpor,

   Use eq'n: Vf = Vi - gt;

       Substitute nlang....
 
          0 = 16 m/s - 9.8 m/s^2(t) Note: hindi sinabi(given) ang time, kaya isosolve ntin xa...
           ilipat sa kaliwang eq'n ang may negative sign para ma-satisfy ang equation...(wOw! )

           9.8 m/s^2(t) = 16 m/s (idivide both sides ng eq'n sa 9.8m/s^2)
           
            so,      t = 1.633 seconds  <-- answer   

To solve for s(distance traveled by the stone. Use eq'n : s = vit + 1/2gt^2)

ayan ho.... Direct substitution na lamang po yan...
Do your part naman.,atleast mapractice moh...

   

[LTSGü]

pwede din yan sa calculus!! XD

a) a=vdv/dx

    a=-9.8m/s^2
   
    separation of variables then integrate both sides:
   
    integ[0-x] -9.8 dx= integ[16-0] vdv

     -9.8x = -128
   
      x=13.061m   <<----












b)
since given ang velocity and acceleration, eto ung formula na nagrerelate sa kanila:

a= dv/dt

a=-9.8m/s^2

integ[0-t] (-9.8m/s^2) dt= integ[16-0] dv

-9.8t=-6

t=1.63265s

but the time to go up is equal to the time to go down..
therefore the time needed for the object to reach the ground is

2*1.633 = 3.66sec <----


wala lang.. para maiba lang ung approach... XD

"masaya gamitin ang calculus"- teacher ko

[m4go10]

waahh!! bakit sabi sa isang thread, bawal daw magsagot ng assignment d2..nasolve ko nrn po eh, but anyways, tnx prn po lalo n dun sa my calculus approach, mas pinagulo niya utak ko..haha!!
pero i will improve my weaknesses

thanks po ulit

[m4go10]

nakakatuwa... napaka detailed pati solution meron

[katherineil]

        s = Vit + 1/2gt^2
        Vf = Vi +/- gt (+g if the object goes downward/same direction of the pull of gravity.)
                              (-g if the object goes upward/opposite direction to the pull of gravity.)
 

...comment ko lng...

[katherineil]

        s = Vit + 1/2gt^2
        Vf = Vi +/- gt (+g if the object goes downward/same direction of the pull of gravity.)
                              (-g if the object goes upward/opposite direction to the pull of gravity.)
 

...comment ko lng...
g is always negative since it is always a negative vector that points downward by convention
negative and positive values he is talking about is the direction of the velocity whereas upward velocity is negative and downward velocity is negative since it is a vector...

..try nyo through transposition nagnenegative at nagpopositive ung g kaya ganun ung naging formula para mas maintindihan pagtinuro sa klc...